(A+3)=9[a-(10-a)]

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Solution for (A+3)=9[a-(10-a)] equation:


Simplifying
(A + 3) = 9[a + -1(10 + -1a)]

Reorder the terms:
(3 + A) = 9[a + -1(10 + -1a)]

Remove parenthesis around (3 + A)
3 + A = 9[a + -1(10 + -1a)]
3 + A = 9[a + (10 * -1 + -1a * -1)]
3 + A = 9[a + (-10 + 1a)]

Reorder the terms:
3 + A = 9[-10 + a + 1a]

Combine like terms: a + 1a = 2a
3 + A = 9[-10 + 2a]
3 + A = [-10 * 9 + 2a * 9]
3 + A = [-90 + 18a]

Solving
3 + A = -90 + 18a

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + A = -90 + -3 + 18a

Combine like terms: 3 + -3 = 0
0 + A = -90 + -3 + 18a
A = -90 + -3 + 18a

Combine like terms: -90 + -3 = -93
A = -93 + 18a

Simplifying
A = -93 + 18a

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